What is (x^2)/(20)-((y+1)^2)/(10)=1 ?

The solution to (x^2)/(20)-((y+1)^2)/(10)=1 is Hyperbola with (h,k)=(0,-1),a=2sqrt(5),b=sqrt(10)

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(x^2)/(20)-((y+1)^2)/(10)=1

\frac{x ^{2}}{20} - \frac{( y + 1 ) ^{2}}{10} = 1

(h, k) = (0, - 1), a = 25, b = 10

Solution steps

\frac{x ^{2}}{20} - \frac{( y + 1 ) ^{2}}{10} = 1

Rewrite

\frac{x ^{2}}{20} - \frac{( y + 1 ) ^{2}}{10} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 2 5 ) ^{2}} - \frac{( y - ( - 1 ) ) ^{2}}{( 10 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, - 1), a = 25, b = 10

4 x^{2} - 9 y^{2} = 1

\frac{( x - 3 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{36} = 1

x^{2} - y^{2} + 4 y = 0

\frac{x ^{2}}{65} - \frac{y ^{2}}{65} = 1

x^{2} - y^{2} + 4 y = 1

What is (x^2)/(20)-((y+1)^2)/(10)=1 ?
The solution to (x^2)/(20)-((y+1)^2)/(10)=1 is Hyperbola with (h,k)=(0,-1),a=2sqrt(5),b=sqrt(10)