What is x^2-2y^2<= 3 ?

The solution to x^2-2y^2<= 3 is Hyperbola with (h,k)=(0,0),a=sqrt(3),b=sqrt(3/2)

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x^2-2y^2<= 3

x^{2} - 2 y^{2} \leq 3

(h, k) = (0, 0), a = 3, b = \frac{3}{2}

Solution steps

x^{2} - 2 y^{2} \leq 3

Rewrite

x^{2} - 2 y^{2} \leq 3

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 3 ) ^{2}} - \frac{( y - 0 ) ^{2}}{( \frac{3}{2} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 3, b = \frac{3}{2}

2 x^{2} - y^{2} + 12 x - 8 y + 3 = 0

\frac{( x + 3 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{5} = 1

16 y^{(2)} - x^{(2)} + 2 x + 64 y - 1 = 0

(\frac{x}{7})^{2} - (\frac{y}{9})^{2} = 1

1 = 2 z^{2} - y^{2}

What is x^2-2y^2<= 3 ?
The solution to x^2-2y^2<= 3 is Hyperbola with (h,k)=(0,0),a=sqrt(3),b=sqrt(3/2)