What is ((y-7)^2)/(36)-((x-3)^2)/(64)=1 ?

The solution to ((y-7)^2)/(36)-((x-3)^2)/(64)=1 is Hyperbola with (h,k)=(3,7),a=6,b=8

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((y-7)^2)/(36)-((x-3)^2)/(64)=1

\frac{( y - 7 ) ^{2}}{36} - \frac{( x - 3 ) ^{2}}{64} = 1

(h, k) = (3, 7), a = 6, b = 8

Solution steps

\frac{( y - 7 ) ^{2}}{36} - \frac{( x - 3 ) ^{2}}{64} = 1

Rewrite

\frac{( y - 7 ) ^{2}}{36} - \frac{( x - 3 ) ^{2}}{64} = 1

in the form of a standard hyperbola equation

\frac{( y - 7 ) ^{2}}{6 ^{2}} - \frac{( x - 3 ) ^{2}}{8 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, 7), a = 6, b = 8

- 3 (x^{2} - 2 x + 1) + (y^{2} + 4 y + 2) - 2 = - 11

x^{2} - y = y^{2}

y^{2} = x^{2} - 2 x

x^{2} - y^{2} - 2 x - 4 y - 7 = 0

\frac{( y - 4 ) ^{2}}{25} - \frac{( x + 1 ) ^{2}}{4} = 1

What is ((y-7)^2)/(36)-((x-3)^2)/(64)=1 ?
The solution to ((y-7)^2)/(36)-((x-3)^2)/(64)=1 is Hyperbola with (h,k)=(3,7),a=6,b=8