What is ((x-0)^2)/(3^2)-((y-0)^2)/(4^2)=1 ?

The solution to ((x-0)^2)/(3^2)-((y-0)^2)/(4^2)=1 is Hyperbola with (h,k)=(0,0),a=3,b=4

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((x-0)^2)/(3^2)-((y-0)^2)/(4^2)=1

\frac{( x - 0 ) ^{2}}{3 ^{2}} - \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

(h, k) = (0, 0), a = 3, b = 4

Solution steps

\frac{( x - 0 ) ^{2}}{3 ^{2}} - \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 3, b = 4

x^{2} - 4 y^{2} + 2 x + 16 y - 11 = 0

2 x^{2} - 3 y^{2} = 1

9 x^{2} - 4 y^{2} + 36 x - 16 y - 16 = 0

y^{2} = - 0.8944 + 1.125 x^{2}

\frac{( y - 1 ) ^{2}}{9} - \frac{( x - 4 ) ^{2}}{4} = 1

What is ((x-0)^2)/(3^2)-((y-0)^2)/(4^2)=1 ?
The solution to ((x-0)^2)/(3^2)-((y-0)^2)/(4^2)=1 is Hyperbola with (h,k)=(0,0),a=3,b=4