What is 1+y^2=x^2(10/4) ?

The solution to 1+y^2=x^2(10/4) is Hyperbola with (h,k)=(0,0),a=sqrt(2/5),b=1

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1+y^2=x^2(10/4)

1 + y^{2} = x^{2} (\frac{10}{4})

(h, k) = (0, 0), a = \frac{2}{5}, b = 1

Solution steps

1 + y^{2} = x^{2} \frac{10}{4}

Rewrite

1 + y^{2} = x^{2} \frac{10}{4}

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( \frac{2}{5} ) ^{2}} - \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = \frac{2}{5}, b = 1

(\frac{x ^{2}}{16}) - (\frac{( y + 4 ) ^{2}}{81}) = 1

16 x^{2} + 96 x - 9 y^{2} + 54 y + 207 = 0

4 x^{2} - 25 y^{2} + 16 x + 50 y - 109 = 0

- y^{2} + x^{2} + 26 y - 26 x = - 121

(y + 2)^{2} - 25 (x - 2)^{2} = 25

What is 1+y^2=x^2(10/4) ?
The solution to 1+y^2=x^2(10/4) is Hyperbola with (h,k)=(0,0),a=sqrt(2/5),b=1