What is 3x^2-6x-y^2-4y-4=0 ?

The solution to 3x^2-6x-y^2-4y-4=0 is Hyperbola with (h,k)=(1,-2),a=1,b=sqrt(3)

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3x^2-6x-y^2-4y-4=0

3 x^{2} - 6 x - y^{2} - 4 y - 4 = 0

(h, k) = (1, - 2), a = 1, b = 3

Solution steps

3 x^{2} - 6 x - y^{2} - 4 y - 4 = 0

Rewrite

3 x^{2} - 6 x - y^{2} - 4 y - 4 = 0

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{1 ^{2}} - \frac{( y - ( - 2 ) ) ^{2}}{( 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 2), a = 1, b = 3

4 y^{2} - 4 x^{2} + 1^{2} = 4

8 x + 2 y^{2} = 3 x^{2} + 3 y

x^{2} - 3 y^{2} - 8 x - 18 y = 14

[f (x)]^{2} = 4 x^{2} - x + 3

2 x^{2} - 3 y^{2} - 6 = 0

What is 3x^2-6x-y^2-4y-4=0 ?
The solution to 3x^2-6x-y^2-4y-4=0 is Hyperbola with (h,k)=(1,-2),a=1,b=sqrt(3)