What is ((x-2)^2)/4-(((y-2))/5)^2=1 ?

The solution to ((x-2)^2)/4-(((y-2))/5)^2=1 is Hyperbola with (h,k)=(2,2),a=2,b=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-2)^2)/4-(((y-2))/5)^2=1

\frac{( x - 2 ) ^{2}}{4} - (\frac{( y - 2 )}{5})^{2} = 1

(h, k) = (2, 2), a = 2, b = 5

Solution steps

\frac{( x - 2 ) ^{2}}{4} - (\frac{y - 2}{5})^{2} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{4} - (\frac{y - 2}{5})^{2} = 1

in the form of a standard hyperbola equation

\frac{( x - 2 ) ^{2}}{2 ^{2}} - \frac{( y - 2 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, 2), a = 2, b = 5

\frac{x ^{2}}{5} - \frac{y ^{2}}{7} = 1

\frac{x ^{2}}{5 ^{2}} - \frac{y ^{2}}{3 ^{2}} = 1

\frac{( x + 2 ) ^{2}}{9} - \frac{y ^{2}}{4} = 1

- 4 x^{2} + 4 y^{2} - 24 x + 32 y = - 24

8 x^{2} - 15 y^{2} = 24

What is ((x-2)^2)/4-(((y-2))/5)^2=1 ?
The solution to ((x-2)^2)/4-(((y-2))/5)^2=1 is Hyperbola with (h,k)=(2,2),a=2,b=5