What is 16-x^2+y^2>= 0 ?

The solution to 16-x^2+y^2>= 0 is Hyperbola with (h,k)=(0,0),a=4,b=4

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16-x^2+y^2>= 0

16 - x^{2} + y^{2} \geq 0

(h, k) = (0, 0), a = 4, b = 4

Solution steps

16 - x^{2} + y^{2} \geq 0

Rewrite

16 - x^{2} + y^{2} \geq 0

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 4

z^{2} - y^{2} = 4

12 y^{2} - 4 x^{2} + 24 x - 24 y - 51 = 0

4 y^{2} - 9 x^{2} - 36 x + 8 y = 0

16.99 y^{2} = 32 + 15.93 x^{2}

25 x^{2} - 200 x - 9 y^{2} + 36 y = 139

What is 16-x^2+y^2>= 0 ?
The solution to 16-x^2+y^2>= 0 is Hyperbola with (h,k)=(0,0),a=4,b=4