What is ((y-1)^2)/4-((x+8)^2)/(25)=1 ?

The solution to ((y-1)^2)/4-((x+8)^2)/(25)=1 is Hyperbola with (h,k)=(-8,1),a=2,b=5

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((y-1)^2)/4-((x+8)^2)/(25)=1

\frac{( y - 1 ) ^{2}}{4} - \frac{( x + 8 ) ^{2}}{25} = 1

(h, k) = (- 8, 1), a = 2, b = 5

Solution steps

\frac{( y - 1 ) ^{2}}{4} - \frac{( x + 8 ) ^{2}}{25} = 1

Rewrite

\frac{( y - 1 ) ^{2}}{4} - \frac{( x + 8 ) ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( y - 1 ) ^{2}}{2 ^{2}} - \frac{( x - ( - 8 ) ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 8, 1), a = 2, b = 5

3 x^{2} - 4 y^{2} + 3 x + 16 y - 18 = 0

\frac{( x - 5 ) ^{2}}{8 ^{2}} - \frac{( y - 2 ) ^{2}}{6 ^{2}} = 1

4 y^{2} - x^{2} = 900

\frac{( x - 2.5 ) ^{2}}{2. 5 ^{2}} - \frac{( y - 5 ) ^{2}}{5 ^{2}} = 1

x^{2} - 2 y^{2} = - 1

What is ((y-1)^2)/4-((x+8)^2)/(25)=1 ?
The solution to ((y-1)^2)/4-((x+8)^2)/(25)=1 is Hyperbola with (h,k)=(-8,1),a=2,b=5