What is (((x+3))/4)^2-(((y-2))/2)^2=1 ?

The solution to (((x+3))/4)^2-(((y-2))/2)^2=1 is Hyperbola with (h,k)=(-3,2),a=4,b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(((x+3))/4)^2-(((y-2))/2)^2=1

(\frac{( x + 3 )}{4})^{2} - (\frac{( y - 2 )}{2})^{2} = 1

(h, k) = (- 3, 2), a = 4, b = 2

Solution steps

(\frac{x + 3}{4})^{2} - (\frac{y - 2}{2})^{2} = 1

Rewrite

(\frac{x + 3}{4})^{2} - (\frac{y - 2}{2})^{2} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 3 ) ) ^{2}}{4 ^{2}} - \frac{( y - 2 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 3, 2), a = 4, b = 2

y^{2} = 8 + 4 x^{2}

(x - 2)^{2} - (y - 4)^{2} = 2

x^{2} - y^{2} \leq 16

x^{2} + 25 = y^{2}

x^{2} - y^{2} - 2 x - y + 1 = 0

What is (((x+3))/4)^2-(((y-2))/2)^2=1 ?
The solution to (((x+3))/4)^2-(((y-2))/2)^2=1 is Hyperbola with (h,k)=(-3,2),a=4,b=2