What is ((K(x))/2)^2=4096+4096-128x+x^2 ?

The solution to ((K(x))/2)^2=4096+4096-128x+x^2 is Hyperbola with (h,k)=(64,0),a=128,b=64

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((K(x))/2)^2=4096+4096-128x+x^2

(\frac{K ( x )}{2})^{2} = 4096 + 4096 - 128 x + x^{2}

(h, k) = (64, 0), a = 128, b = 64

Solution steps

(\frac{y}{2})^{2} = 4096 + 4096 - 128 x + x^{2}

Rewrite

(\frac{y}{2})^{2} - 4096 - 4096 + 128 x - x^{2} = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{12 8 ^{2}} - \frac{( x - 64 ) ^{2}}{6 4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (64, 0), a = 128, b = 64

1 \cdot 3 = (a + b) (a - b)

x^{2} - y^{2} = - (1)

x, 2 x^{2} - 28 x + 196 = r (x)^{2}

- x^{2} + y^{2} = - 11

x^{2} - 4 y^{2} - 6 x - 16 y - 16 = 0

What is ((K(x))/2)^2=4096+4096-128x+x^2 ?
The solution to ((K(x))/2)^2=4096+4096-128x+x^2 is Hyperbola with (h,k)=(64,0),a=128,b=64