What is ((y-4)^2}{25}-\frac{(x+6)^2)/9 =1 ?

The solution to ((y-4)^2}{25}-\frac{(x+6)^2)/9 =1 is Hyperbola with (h,k)=(-6,4),a=5,b=3

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((y-4)^2}{25}-\frac{(x+6)^2)/9 =1

\frac{( y - 4 ) ^{2}}{25} - \frac{( x + 6 ) ^{2}}{9} = 1

(h, k) = (- 6, 4), a = 5, b = 3

Solution steps

\frac{( y - 4 ) ^{2}}{25} - \frac{( x + 6 ) ^{2}}{9} = 1

Rewrite

\frac{( y - 4 ) ^{2}}{25} - \frac{( x + 6 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( y - 4 ) ^{2}}{5 ^{2}} - \frac{( x - ( - 6 ) ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 6, 4), a = 5, b = 3

x^{2} - 2 x - y^{2} = 1

- x^{2} + y^{2} = 16

- x^{2} + y^{2} = 12

\frac{x ^{2}}{8} - \frac{y ^{2}}{4} = 1

\frac{( y + 3 ) ^{2}}{64} - \frac{( x + 6 ) ^{2}}{49} = 1

What is ((y-4)^2}{25}-\frac{(x+6)^2)/9 =1 ?
The solution to ((y-4)^2}{25}-\frac{(x+6)^2)/9 =1 is Hyperbola with (h,k)=(-6,4),a=5,b=3