What is ((y-4)^2)/9-((x-2)^2)/(16)=1 ?

The solution to ((y-4)^2)/9-((x-2)^2)/(16)=1 is Hyperbola with (h,k)=(2,4),a=3,b=4

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((y-4)^2)/9-((x-2)^2)/(16)=1

\frac{( y - 4 ) ^{2}}{9} - \frac{( x - 2 ) ^{2}}{16} = 1

(h, k) = (2, 4), a = 3, b = 4

Solution steps

\frac{( y - 4 ) ^{2}}{9} - \frac{( x - 2 ) ^{2}}{16} = 1

Rewrite

\frac{( y - 4 ) ^{2}}{9} - \frac{( x - 2 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - 4 ) ^{2}}{3 ^{2}} - \frac{( x - 2 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, 4), a = 3, b = 4

9 x^{2} - 36 x - y^{2} - 6 y + 18 = 0

x^{2} - y^{2} - y + 9 = 0

16 x^{2} - 9 y^{2} - 96 x + 36 y - 36 = 0

\frac{x ^{2}}{2 ^{2}} - \frac{y ^{2}}{4 ^{2}} = - 1

\frac{( x + 1 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{4} = 1

What is ((y-4)^2)/9-((x-2)^2)/(16)=1 ?
The solution to ((y-4)^2)/9-((x-2)^2)/(16)=1 is Hyperbola with (h,k)=(2,4),a=3,b=4