What is (((x-2)^2))/4-(((y+1)^2))/9 =1 ?

The solution to (((x-2)^2))/4-(((y+1)^2))/9 =1 is Hyperbola with (h,k)=(2,-1),a=2,b=3

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(((x-2)^2))/4-(((y+1)^2))/9 =1

\frac{( ( x - 2 ) ^{2} )}{4} - \frac{( ( y + 1 ) ^{2} )}{9} = 1

(h, k) = (2, - 1), a = 2, b = 3

Solution steps

\frac{( x - 2 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{9} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 2 ) ^{2}}{2 ^{2}} - \frac{( y - ( - 1 ) ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, - 1), a = 2, b = 3

5 x^{2} - 4 y^{2} - 20 = 0

4 x^{2} - 25 y^{2} + 50 y - 125 = 0

f (x) f (x) = x^{2} - x + 1

- 9 x^{2} + 4 y^{2} - 108 x + 32 y - 296 = 0

\frac{( x - 1 ) ^{2}}{9} - \frac{y ^{2}}{5} = 100

What is (((x-2)^2))/4-(((y+1)^2))/9 =1 ?
The solution to (((x-2)^2))/4-(((y+1)^2))/9 =1 is Hyperbola with (h,k)=(2,-1),a=2,b=3