What is -x^2-16x+4y^2-12y+16=0 ?

The solution to -x^2-16x+4y^2-12y+16=0 is Hyperbola with (h,k)=(-8, 3/2),a=sqrt(71),b=(sqrt(71))/2

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-x^2-16x+4y^2-12y+16=0

- x^{2} - 16 x + 4 y^{2} - 12 y + 16 = 0

(h, k) = (- 8, \frac{3}{2}), a = 71, b = \frac{71}{2}

Solution steps

- x^{2} - 16 x + 4 y^{2} - 12 y + 16 = 0

Rewrite

- x^{2} - 16 x + 4 y^{2} - 12 y + 16 = 0

in the form of a standard hyperbola equation

\frac{( x - ( - 8 ) ) ^{2}}{( 71 ) ^{2}} - \frac{( y - \frac{3}{2} ) ^{2}}{( \frac{71}{2} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 8, \frac{3}{2}), a = 71, b = \frac{71}{2}

9 x^{2} - 4 y^{2} - 18 x + 18 y + 10 = 0

\frac{( x - 3 ) ^{2}}{9} - \frac{( y - 2 ) ^{2}}{16} = 1

a^{2} - b^{2} = 2017

\frac{( y + 3 ) ^{2}}{1} - \frac{( x + 2 ) ^{2}}{3} = 1

1 = aa - bb

What is -x^2-16x+4y^2-12y+16=0 ?
The solution to -x^2-16x+4y^2-12y+16=0 is Hyperbola with (h,k)=(-8, 3/2),a=sqrt(71),b=(sqrt(71))/2