What is 4y^2+24x+12y-39=0 ?

The solution to 4y^2+24x+12y-39=0 is Parabola with (h,k)=(2,-3/2),p=-3/2

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4y^2+24x+12y-39=0

4 y^{2} + 24 x + 12 y - 39 = 0

(h, k) = (2, - \frac{3}{2}), p = - \frac{3}{2}

Solution steps

4 y^{2} + 24 x + 12 y - 39 = 0

Rewrite

4 y^{2} + 24 x + 12 y - 39 = 0

in the standard form

4 (- \frac{3}{2}) (x - 2) = (y - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (2, - \frac{3}{2}), p = - \frac{3}{2}

0 = y^{2} - 4 y - 2 - x

- 3 x^{2} + 2 y = 5 x + 3 y - 8

y^{2} = - 5 x

4 x^{2} + 24 x - y + 38 = 0

x^{2} - 4 x - 2 y + 2 = 0

What is 4y^2+24x+12y-39=0 ?
The solution to 4y^2+24x+12y-39=0 is Parabola with (h,k)=(2,-3/2),p=-3/2