What is ((x+1)^2)/4-((y-2)^2)/(16)=1 ?

The solution to ((x+1)^2)/4-((y-2)^2)/(16)=1 is Hyperbola with (h,k)=(-1,2),a=2,b=4

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((x+1)^2)/4-((y-2)^2)/(16)=1

\frac{( x + 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{16} = 1

(h, k) = (- 1, 2), a = 2, b = 4

Solution steps

\frac{( x + 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{16} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 1 ) ) ^{2}}{2 ^{2}} - \frac{( y - 2 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 2), a = 2, b = 4

\frac{( x - 2 ) ^{2}}{7} - \frac{( y + 1 ) ^{2}}{9} = 1

x^{2} = - 2 y + y^{2}

8 y^{2} - x^{2} - 16 y + 8 x - 32 = 0

2 x^{2} - y^{2} + 4 x + 2 y - 3 = 0

5 x^{2} - 2 y^{2} = 9

What is ((x+1)^2)/4-((y-2)^2)/(16)=1 ?
The solution to ((x+1)^2)/4-((y-2)^2)/(16)=1 is Hyperbola with (h,k)=(-1,2),a=2,b=4