What is ((x-0)^2)/4-((y-(-1))^2)/(16)=1 ?

The solution to ((x-0)^2)/4-((y-(-1))^2)/(16)=1 is Hyperbola with (h,k)=(0,-1),a=2,b=4

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((x-0)^2)/4-((y-(-1))^2)/(16)=1

\frac{( x - 0 ) ^{2}}{4} - \frac{( y - ( - 1 ) ) ^{2}}{16} = 1

(h, k) = (0, - 1), a = 2, b = 4

Solution steps

\frac{( x - 0 ) ^{2}}{4} - \frac{( y - ( - 1 ) ) ^{2}}{16} = 1

Rewrite

\frac{( x - 0 ) ^{2}}{4} - \frac{( y - ( - 1 ) ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - ( - 1 ) ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, - 1), a = 2, b = 4

\frac{y ^{2}}{2} + 3 y = \frac{x ^{2}}{2}

20 (x - y) = 5 x^{2} - 4 y^{2}

\frac{y ^{2}}{5} - \frac{x ^{2}}{25} = 1

\frac{x ^{2} + 1}{4} - \frac{y ^{2} - 2}{9} = - 1

36 x^{2} - 9 y^{2} + 216 x + 36 y = - 207

What is ((x-0)^2)/4-((y-(-1))^2)/(16)=1 ?
The solution to ((x-0)^2)/4-((y-(-1))^2)/(16)=1 is Hyperbola with (h,k)=(0,-1),a=2,b=4