What is (x^2)/9-(y^2)/(27)=1 ?

The solution to (x^2)/9-(y^2)/(27)=1 is Hyperbola with (h,k)=(0,0),a=3,b=3sqrt(3)

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(x^2)/9-(y^2)/(27)=1

\frac{x ^{2}}{9} - \frac{y ^{2}}{27} = 1

(h, k) = (0, 0), a = 3, b = 33

Solution steps

\frac{x ^{2}}{9} - \frac{y ^{2}}{27} = 1

Rewrite

\frac{x ^{2}}{9} - \frac{y ^{2}}{27} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} - \frac{( y - 0 ) ^{2}}{( 3 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 3, b = 33

6 x^{2} - 3 y^{2} = 3

\frac{( y + 4 ) ^{2}}{64} - \frac{( x + 3 ) ^{2}}{25} = 1

\frac{( 4 x ^{2} - 4 y ^{2} - 4 )}{( x ^{2} + y ^{2} + 1 ) ^{2}} = 0

f (x) (f (x)) = 2 x^{2} - 3 x + 2

\frac{y ^{2}}{21} - \frac{x ^{2}}{13} = 1

What is (x^2)/9-(y^2)/(27)=1 ?
The solution to (x^2)/9-(y^2)/(27)=1 is Hyperbola with (h,k)=(0,0),a=3,b=3sqrt(3)