What is ((y+3)^2)/(64)-((x+1)^2)/(36)=1 ?

The solution to ((y+3)^2)/(64)-((x+1)^2)/(36)=1 is Hyperbola with (h,k)=(-1,-3),a=8,b=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((y+3)^2)/(64)-((x+1)^2)/(36)=1

\frac{( y + 3 ) ^{2}}{64} - \frac{( x + 1 ) ^{2}}{36} = 1

(h, k) = (- 1, - 3), a = 8, b = 6

Solution steps

\frac{( y + 3 ) ^{2}}{64} - \frac{( x + 1 ) ^{2}}{36} = 1

Rewrite

\frac{( y + 3 ) ^{2}}{64} - \frac{( x + 1 ) ^{2}}{36} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 3 ) ) ^{2}}{8 ^{2}} - \frac{( x - ( - 1 ) ) ^{2}}{6 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, - 3), a = 8, b = 6

- 4 x^{2} + 9 y^{2} + 24 x - 36 y - 32 = 0

\frac{x ^{2}}{24} - \frac{y ^{2}}{9} = 1

x^{2} - y^{2} - 6 y = 0

4 y^{2} - 4 x^{2} = 4

x^{(2)} - y^{(2)} = 25

What is ((y+3)^2)/(64)-((x+1)^2)/(36)=1 ?
The solution to ((y+3)^2)/(64)-((x+1)^2)/(36)=1 is Hyperbola with (h,k)=(-1,-3),a=8,b=6