What is ((x+4)^2)/4-((y-8)^2)/(16)=1 ?

The solution to ((x+4)^2)/4-((y-8)^2)/(16)=1 is Hyperbola with (h,k)=(-4,8),a=2,b=4

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((x+4)^2)/4-((y-8)^2)/(16)=1

\frac{( x + 4 ) ^{2}}{4} - \frac{( y - 8 ) ^{2}}{16} = 1

(h, k) = (- 4, 8), a = 2, b = 4

Solution steps

\frac{( x + 4 ) ^{2}}{4} - \frac{( y - 8 ) ^{2}}{16} = 1

Rewrite

\frac{( x + 4 ) ^{2}}{4} - \frac{( y - 8 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 4 ) ) ^{2}}{2 ^{2}} - \frac{( y - 8 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 4, 8), a = 2, b = 4

25 x^{2} - 16 y^{2} - 400 = 0

x^{2} - \frac{y ^{2}}{10} = 5

5 x^{2} - 3 y^{2} - 20 x - 18 y - 22 = 0

\frac{x ^{2}}{8} - \frac{y ^{2}}{8} = 1

- 4 x^{2} + 9 y^{2} - 24 x - 54 y + 81 = 0

What is ((x+4)^2)/4-((y-8)^2)/(16)=1 ?
The solution to ((x+4)^2)/4-((y-8)^2)/(16)=1 is Hyperbola with (h,k)=(-4,8),a=2,b=4