What is ((y+5)^2)/9-((x-3)^2)/(25)=1 ?

The solution to ((y+5)^2)/9-((x-3)^2)/(25)=1 is Hyperbola with (h,k)=(3,-5),a=3,b=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((y+5)^2)/9-((x-3)^2)/(25)=1

\frac{( y + 5 ) ^{2}}{9} - \frac{( x - 3 ) ^{2}}{25} = 1

(h, k) = (3, - 5), a = 3, b = 5

Solution steps

\frac{( y + 5 ) ^{2}}{9} - \frac{( x - 3 ) ^{2}}{25} = 1

Rewrite

\frac{( y + 5 ) ^{2}}{9} - \frac{( x - 3 ) ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 5 ) ) ^{2}}{3 ^{2}} - \frac{( x - 3 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, - 5), a = 3, b = 5

\frac{( x - 3 ) ^{2}}{16} - \frac{( y + 2 ) ^{2}}{16} = 1

x^{2} - y^{2} = \frac{64}{5}

y^{2} = x^{2} - 5 x + 4

a^{2} - b^{2} = 50

x^{2} - 9 = 2 y^{2}

What is ((y+5)^2)/9-((x-3)^2)/(25)=1 ?
The solution to ((y+5)^2)/9-((x-3)^2)/(25)=1 is Hyperbola with (h,k)=(3,-5),a=3,b=5