What is ((x-4)^2)/9-((y-2)^2)/4 =1 ?

The solution to ((x-4)^2)/9-((y-2)^2)/4 =1 is Hyperbola with (h,k)=(4,2),a=3,b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-4)^2)/9-((y-2)^2)/4 =1

\frac{( x - 4 ) ^{2}}{9} - \frac{( y - 2 ) ^{2}}{4} = 1

(h, k) = (4, 2), a = 3, b = 2

Solution steps

\frac{( x - 4 ) ^{2}}{9} - \frac{( y - 2 ) ^{2}}{4} = 1

Rewrite

\frac{( x - 4 ) ^{2}}{9} - \frac{( y - 2 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - 4 ) ^{2}}{3 ^{2}} - \frac{( y - 2 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (4, 2), a = 3, b = 2

a^{2} - b^{2} = 31

9 y^{2} - 25 x^{2} + 54 y + 150 x = 369

y^{2} = 8^{2} + x^{2}

a^{2} - b^{2} = - 5

\frac{( x - 4 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{9} = 1

What is ((x-4)^2)/9-((y-2)^2)/4 =1 ?
The solution to ((x-4)^2)/9-((y-2)^2)/4 =1 is Hyperbola with (h,k)=(4,2),a=3,b=2