What is ((x-4)^2)/9-((Y(x)+1)^2)/4 =1 ?

The solution to ((x-4)^2)/9-((Y(x)+1)^2)/4 =1 is Hyperbola with (h,k)=(4,-1),a=3,b=2

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((x-4)^2)/9-((Y(x)+1)^2)/4 =1

\frac{( x - 4 ) ^{2}}{9} - \frac{( Y ( x ) + 1 ) ^{2}}{4} = 1

(h, k) = (4, - 1), a = 3, b = 2

Solution steps

\frac{( x - 4 ) ^{2}}{9} - \frac{( y + 1 ) ^{2}}{4} = 1

Rewrite

\frac{( x - 4 ) ^{2}}{9} - \frac{( y + 1 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - 4 ) ^{2}}{3 ^{2}} - \frac{( y - ( - 1 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (4, - 1), a = 3, b = 2

\frac{( x - 2 ) ^{2}}{16} - \frac{( y - 3 ) ^{2}}{9} = 1

x^{2} - y^{2} = y

4 x^{2} - 6 y^{2} = 24

9 x^{2} - 2 y^{2} = 18

7^{2} + b^{2} = (c + 1)^{2}

What is ((x-4)^2)/9-((Y(x)+1)^2)/4 =1 ?
The solution to ((x-4)^2)/9-((Y(x)+1)^2)/4 =1 is Hyperbola with (h,k)=(4,-1),a=3,b=2