What is 16x^2-9y^2-32x+36y+124=0 ?

The solution to 16x^2-9y^2-32x+36y+124=0 is Hyperbola with (h,k)=(1,2),a=4,b=3

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16x^2-9y^2-32x+36y+124=0

16 x^{2} - 9 y^{2} - 32 x + 36 y + 124 = 0

(h, k) = (1, 2), a = 4, b = 3

Solution steps

16 x^{2} - 9 y^{2} - 32 x + 36 y + 124 = 0

Rewrite

16 x^{2} - 9 y^{2} - 32 x + 36 y + 124 = 0

in the form of a standard hyperbola equation

\frac{( y - 2 ) ^{2}}{4 ^{2}} - \frac{( x - 1 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, 2), a = 4, b = 3

4 y^{2} - 3 x^{2} - 8 y + 6 x - 3 = 0

- x^{2} + 9 y^{2} + 90 y + 189 = 0

\frac{( x ^{2} )}{625} - \frac{( y ^{2} )}{3600} = 1

\frac{x ^{2}}{16} - (y - 7)^{2} = 1

x^{2} - 4 x - y^{2} + 4 y - 2 = 0

What is 16x^2-9y^2-32x+36y+124=0 ?
The solution to 16x^2-9y^2-32x+36y+124=0 is Hyperbola with (h,k)=(1,2),a=4,b=3