What is y^{(2)}-x^{(2)}=(1/49) ?

The solution to y^{(2)}-x^{(2)}=(1/49) is Hyperbola with (h,k)=(0,0),a= 1/7 ,b= 1/7

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y^{(2)}-x^{(2)}=(1/49)

y^{(2)} - x^{(2)} = (\frac{1}{49})

(h, k) = (0, 0), a = \frac{1}{7}, b = \frac{1}{7}

Solution steps

y^{2} - x^{2} = \frac{1}{49}

Rewrite

y^{2} - x^{2} = \frac{1}{49}

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{( \frac{1}{7} ) ^{2}} - \frac{( x - 0 ) ^{2}}{( \frac{1}{7} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = \frac{1}{7}, b = \frac{1}{7}

9 x^{2} - 4 y^{2} - 72 x + 8 y + 17 = 0

a^{2} - b^{2} = 300

a^{2} + 1 5^{2} = c^{2}

9 x^{2} - 72 x - 16 y^{2} - 32 y = 16

16 x^{2} - y^{2} + 16 y - 128 = 0

What is y^{(2)}-x^{(2)}=(1/49) ?
The solution to y^{(2)}-x^{(2)}=(1/49) is Hyperbola with (h,k)=(0,0),a= 1/7 ,b= 1/7