What is (x^2)/4-(((y+1))/(16))^2=1 ?

The solution to (x^2)/4-(((y+1))/(16))^2=1 is Hyperbola with (h,k)=(0,-1),a=2,b=16

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(x^2)/4-(((y+1))/(16))^2=1

\frac{x ^{2}}{4} - (\frac{( y + 1 )}{16})^{2} = 1

(h, k) = (0, - 1), a = 2, b = 16

Solution steps

\frac{x ^{2}}{4} - (\frac{y + 1}{16})^{2} = 1

Rewrite

\frac{x ^{2}}{4} - (\frac{y + 1}{16})^{2} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - ( - 1 ) ) ^{2}}{1 6 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, - 1), a = 2, b = 16

\frac{x ^{2}}{25} - \frac{y ^{2}}{121} = 1

\frac{( x + 4 ) ^{2}}{25} - \frac{( y - 2 ) ^{2}}{4} = 1

x^{2} - y^{2} - 9 = 3

9 x^{2} - 16 = (4 x + s) (4 x - s)

(\frac{x - 5}{4})^{2} - (\frac{y + 7}{3})^{2} = - 1

What is (x^2)/4-(((y+1))/(16))^2=1 ?
The solution to (x^2)/4-(((y+1))/(16))^2=1 is Hyperbola with (h,k)=(0,-1),a=2,b=16