What is ((x-3)^2)/(36)-((y-2)^2)/(64)=1 ?

The solution to ((x-3)^2)/(36)-((y-2)^2)/(64)=1 is Hyperbola with (h,k)=(3,2),a=6,b=8

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((x-3)^2)/(36)-((y-2)^2)/(64)=1

\frac{( x - 3 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{64} = 1

(h, k) = (3, 2), a = 6, b = 8

Solution steps

\frac{( x - 3 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{64} = 1

Rewrite

\frac{( x - 3 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{64} = 1

in the form of a standard hyperbola equation

\frac{( x - 3 ) ^{2}}{6 ^{2}} - \frac{( y - 2 ) ^{2}}{8 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, 2), a = 6, b = 8

4 x^{2} - 5 y^{2} - 36 y - 36 = 0

y^{2} - 1 = 16 (x^{2} - 1)

5 x^{2} - 4 y^{2} - 18 y + 9 = 0

\frac{( x + 3 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{9} = 1

\frac{( y + 3 ) ^{2}}{81} - \frac{( x + 3 ) ^{2}}{16} = 1

What is ((x-3)^2)/(36)-((y-2)^2)/(64)=1 ?
The solution to ((x-3)^2)/(36)-((y-2)^2)/(64)=1 is Hyperbola with (h,k)=(3,2),a=6,b=8