What is the vertices-9x^2+8y^2+36x+48y=36 ?

The vertices-9x^2+8y^2+36x+48y=36 is (2,0),(2,-6)

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vertices-9x^2+8y^2+36x+48y=36

vertices

- 9 x^{2} + 8 y^{2} + 36 x + 48 y = 36

(2, 0), (2, - 6)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

- 9 x^{2} + 8 y^{2} + 36 x + 48 y = 36 :

Up-down Hyperbola with

(h, k) = (2, - 3), a = 3, b = 22

(2, - 3 + 3), (2, - 3 - 3)

Refine

(2, 0), (2, - 6)

36 x^{2} - y^{2} - 216 x + 10 y + 263 = 0

4 x^{2} - 9 y^{2} - 36 = 0

9 x^{2} - 4 y^{2} - 54 x - 16 y + 29 = 0

25 x^{2} - 16 y^{2} + 50 x + 128 y - 631 = 0

x^{2} - y^{2} + 7 x + 8 y = 5

What is the vertices-9x^2+8y^2+36x+48y=36 ?
The vertices-9x^2+8y^2+36x+48y=36 is (2,0),(2,-6)