What is the vertices (y^2)/1-(x^2)/4 =1 ?

The vertices (y^2)/1-(x^2)/4 =1 is (0,1),(0,-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices (y^2)/1-(x^2)/4 =1

vertices

\frac{y ^{2}}{1} - \frac{x ^{2}}{4} = 1

(0, 1), (0, - 1)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{y ^{2}}{1} - \frac{x ^{2}}{4} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 1, b = 2

(0, 0 + 1), (0, 0 - 1)

Refine

(0, 1), (0, - 1)

9 (x - 1)^{2} - 16 (y + 2)^{2} = 144

9 x^{2} - 4 y^{2} + 54 x + 16 y + 29 = 0

\frac{( y + 3 ) ^{2}}{9} - \frac{( x - 2 ) ^{2}}{16} = 1

9 x^{2} - 18 x - 24 y - 63 = 4 y^{2}

\frac{( x + 4 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{25} = 1

What is the vertices (y^2)/1-(x^2)/4 =1 ?
The vertices (y^2)/1-(x^2)/4 =1 is (0,1),(0,-1)