What is the vertices 144y^2-25x^2=3600 ?

The vertices 144y^2-25x^2=3600 is (0,5),(0,-5)

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vertices 144y^2-25x^2=3600

vertices

144 y^{2} - 25 x^{2} = 3600

(0, 5), (0, - 5)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

144 y^{2} - 25 x^{2} = 3600 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 12

(0, 0 + 5), (0, 0 - 5)

Refine

(0, 5), (0, - 5)

\frac{x ^{2}}{4} - \frac{y ^{2}}{4} = 1

\frac{( y + 2 ) ^{2}}{2} - \frac{( x + 1 ) ^{2}}{2} = 1

4 x^{2} - 25 y^{2} + 16 x + 50 y - 109 = 0

\frac{y ^{2}}{16} - \frac{x ^{2}}{4} = 1

x^{2} - y^{2} - 4 x + 4 y + 9 = 0

What is the vertices 144y^2-25x^2=3600 ?
The vertices 144y^2-25x^2=3600 is (0,5),(0,-5)