What is (y+5)^2=-1/3 (x-3) ?

The solution to (y+5)^2=-1/3 (x-3) is Parabola with (h,k)=(3,-5),p=-1/12

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(y+5)^2=-1/3 (x-3)

(y + 5)^{2} = - \frac{1}{3} (x - 3)

(h, k) = (3, - 5), p = - \frac{1}{12}

Solution steps

(y + 5)^{2} = - \frac{1}{3} (x - 3)

Rewrite

(y + 5)^{2} = - \frac{1}{3} (x - 3)

in the standard form:

4 (- \frac{1}{12}) (x - 3) = (y - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (3, - 5), p = - \frac{1}{12}

24 x^{2} - 6 x + 2 y = 0

(y - (- 19))^{2} = 2 (x - 1)

24 y = 8 x^{2}

y^{2} + 6 y + 20 x + 89 = 0

(x - 4)^{2} = - 8 (y - 3)

What is (y+5)^2=-1/3 (x-3) ?
The solution to (y+5)^2=-1/3 (x-3) is Parabola with (h,k)=(3,-5),p=-1/12