What is the vertices f(x)f(x)=3(x+6)(x+3) ?

The vertices f(x)f(x)=3(x+6)(x+3) is (-3,0),(-6,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices f(x)f(x)=3(x+6)(x+3)

vertices

f (x) f (x) = 3 (x + 6) (x + 3)

(- 3, 0), (- 6, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

yy = 3 (x + 6) (x + 3) :

Right-left Hyperbola with

(h, k) = (- \frac{9}{2}, 0), a = \frac{3}{2}, b = \frac{3 3}{2}

(- \frac{9}{2} + \frac{3}{2}, 0), (- \frac{9}{2} - \frac{3}{2}, 0)

Refine

(- 3, 0), (- 6, 0)

4 x^{2} - 9 y^{2} - 16 x + 18 y - 7 = 0

\frac{x ^{2}}{7} - \frac{y ^{2}}{6} = 1

9 x^{2} - 16 y^{2} + 54 x - 16 y = - 113

(\frac{y - 4}{4})^{2} - (\frac{x - 6}{4})^{2} = 1

4 x^{2} - 9 y^{2} - 16 x - 72 y - 129 = 0

What is the vertices f(x)f(x)=3(x+6)(x+3) ?
The vertices f(x)f(x)=3(x+6)(x+3) is (-3,0),(-6,0)