What is the vertices (y^2)/3-(x^2)/1 =1 ?

The vertices (y^2)/3-(x^2)/1 =1 is (0,sqrt(3)),(0,-sqrt(3))

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vertices (y^2)/3-(x^2)/1 =1

vertices

\frac{y ^{2}}{3} - \frac{x ^{2}}{1} = 1

(0, 3), (0, - 3)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{y ^{2}}{3} - \frac{x ^{2}}{1} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 3, b = 1

(0, 0 + 3), (0, 0 - 3)

Refine

(0, 3), (0, - 3)

4 x^{2} - 5 y^{2} + 30 y = 65

f (x) f (x) = x^{2} + 5 x + 6

\frac{( x + 4 ) ^{2}}{9} - \frac{( y - 8 ) ^{2}}{49} = 1

25 x^{2} - 9 y^{2} - 225 = 0

5 x^{2} - 4 y^{2} - 40 x + 24 y + 24 = 0

What is the vertices (y^2)/3-(x^2)/1 =1 ?
The vertices (y^2)/3-(x^2)/1 =1 is (0,sqrt(3)),(0,-sqrt(3))