What is the vertices (y^2)/(81)-(x^2)/(64)=1 ?

The vertices (y^2)/(81)-(x^2)/(64)=1 is (0,9),(0,-9)

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vertices (y^2)/(81)-(x^2)/(64)=1

vertices

\frac{y ^{2}}{81} - \frac{x ^{2}}{64} = 1

(0, 9), (0, - 9)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{y ^{2}}{81} - \frac{x ^{2}}{64} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 9, b = 8

(0, 0 + 9), (0, 0 - 9)

Refine

(0, 9), (0, - 9)

\frac{( x ) ^{2}}{4} - \frac{( y + 3 ) ^{2}}{9} = 1

4 (y - 3)^{2} - 9 (x - 2)^{2} = 36

\frac{x ^{2}}{36} - \frac{( y - 10 ) ^{2}}{64} = 1

4 x^{2} - y^{2} + 32 x + 10 y + 38 = 0

4 x^{2} - y^{2} + 12 x + 5 = 0

What is the vertices (y^2)/(81)-(x^2)/(64)=1 ?
The vertices (y^2)/(81)-(x^2)/(64)=1 is (0,9),(0,-9)