What is the vertices 4x^2-y^2+24x-4y=4 ?

The vertices 4x^2-y^2+24x-4y=4 is (0,-2),(-6,-2)

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vertices 4x^2-y^2+24x-4y=4

vertices

4 x^{2} - y^{2} + 24 x - 4 y = 4

(0, - 2), (- 6, - 2)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

4 x^{2} - y^{2} + 24 x - 4 y = 4 :

Right-left Hyperbola with

(h, k) = (- 3, - 2), a = 3, b = 6

(- 3 + 3, - 2), (- 3 - 3, - 2)

Refine

(0, - 2), (- 6, - 2)

\frac{( x - 3 ) ^{2}}{3} - \frac{( y - 2 ) ^{2}}{22} = 1

16 x^{2} - 9 y^{2} + 64 x - 90 y = 305

4 x^{2} - 9 y^{2} - 36 < 0

\frac{x ^{2}}{16} - \frac{y ^{2}}{64} = 1

x^{2} - 3 y^{2} + 2 x + 6 y - 1 = 0

What is the vertices 4x^2-y^2+24x-4y=4 ?
The vertices 4x^2-y^2+24x-4y=4 is (0,-2),(-6,-2)