What is the vertices y^2-x^2= 9/25 ?

The vertices y^2-x^2= 9/25 is (0, 3/5),(0,-3/5)

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vertices y^2-x^2= 9/25

vertices

y^{2} - x^{2} = \frac{9}{25}

(0, \frac{3}{5}), (0, - \frac{3}{5})

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

y^{2} - x^{2} = \frac{9}{25} :

Up-down Hyperbola with

(h, k) = (0, 0), a = \frac{3}{5}, b = \frac{3}{5}

(0, 0 + \frac{3}{5}), (0, 0 - \frac{3}{5})

Refine

(0, \frac{3}{5}), (0, - \frac{3}{5})

16 y^{2} - 9 x^{2} + 36 x + 96 y - 36 = 0

- 25 x^{2} + 4 y^{2} = 100

\frac{y ^{2}}{144} - \frac{x ^{2}}{25} = 1

\frac{( x - 3 ) ^{2}}{9} - \frac{( y - 2 ) ^{2}}{4} = 1

\frac{( x + 1 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{8} = 1

What is the vertices y^2-x^2= 9/25 ?
The vertices y^2-x^2= 9/25 is (0, 3/5),(0,-3/5)