What is the vertices 9y^2+36y-4x^2-24x-36=0 ?

The vertices 9y^2+36y-4x^2-24x-36=0 is (-3,0),(-3,-4)

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vertices 9y^2+36y-4x^2-24x-36=0

vertices

9 y^{2} + 36 y - 4 x^{2} - 24 x - 36 = 0

(- 3, 0), (- 3, - 4)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

9 y^{2} + 36 y - 4 x^{2} - 24 x - 36 = 0 :

Up-down Hyperbola with

(h, k) = (- 3, - 2), a = 2, b = 3

(- 3, - 2 + 2), (- 3, - 2 - 2)

Refine

(- 3, 0), (- 3, - 4)

\frac{( x - 8 ) ^{2}}{4} - \frac{( y - 5 ) ^{2}}{9} = 1

x^{2} - y^{2} = 4 x

x^{2} - 6 x - 2 y^{2} + 7 = 0

4 y^{2} - 25 x^{2} = 100

\frac{( x - 3 ) ^{2}}{49} - \frac{( y - 5 ) ^{2}}{15} = 1

What is the vertices 9y^2+36y-4x^2-24x-36=0 ?
The vertices 9y^2+36y-4x^2-24x-36=0 is (-3,0),(-3,-4)