What is the vertices (4x-3y)=(-144)/((4x+3y)) ?

The vertices (4x-3y)=(-144)/((4x+3y)) is (0,4),(0,-4)

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vertices (4x-3y)=(-144)/((4x+3y))

vertices

(4 x - 3 y) = \frac{- 144}{( 4 x + 3 y )}

(0, 4), (0, - 4)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

(4 x - 3 y) = \frac{- 144}{4 x + 3 y} :

Up-down Hyperbola with

(h, k) = (0, 0), a = 4, b = 3

(0, 0 + 4), (0, 0 - 4)

Refine

(0, 4), (0, - 4)

4 y^{2} - 5 x^{2} = 20

\frac{y ^{2}}{25} - \frac{x ^{2}}{49} = 1

(y + 4)^{2} - \frac{( x - 2 ) ^{2}}{4} = 1

- x^{2} + 4 y^{2} + 2 x + 24 y + 31 = 0

9 x^{2} - 4 y^{2} = 144

What is the vertices (4x-3y)=(-144)/((4x+3y)) ?
The vertices (4x-3y)=(-144)/((4x+3y)) is (0,4),(0,-4)