What is the foci (y^2)/(16)-(x^2)/(49)=1 ?

The foci (y^2)/(16)-(x^2)/(49)=1 is (0,sqrt(65)),(0,-sqrt(65))

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foci (y^2)/(16)-(x^2)/(49)=1

foci

\frac{y ^{2}}{16} - \frac{x ^{2}}{49} = 1

(0, 65), (0, - 65)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{16} - \frac{x ^{2}}{49} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 4, b = 7

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 4^{2} + 7^{2} : 65

(0, 0 + 65), (0, 0 - 65)

Refine

(0, 65), (0, - 65)

\frac{y ^{2}}{25} - \frac{x ^{2}}{144} = 1

9 y^{2} - x^{2} + 2 x + 54 y + 62 = 0

16 x^{2} - 25 y^{2} = 400

9 y^{2} - 16 x^{2} = 144

\frac{x ^{2}}{144} - \frac{y ^{2}}{25} = 1

What is the foci (y^2)/(16)-(x^2)/(49)=1 ?
The foci (y^2)/(16)-(x^2)/(49)=1 is (0,sqrt(65)),(0,-sqrt(65))