What is the foci 4x^2-1/2 y^2+8x+2y=2 ?

The foci 4x^2-1/2 y^2+8x+2y=2 is (2,2),(-4,2)

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foci 4x^2-1/2 y^2+8x+2y=2

foci

4 x^{2} - \frac{1}{2} y^{2} + 8 x + 2 y = 2

(2, 2), (- 4, 2)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

4 x^{2} - \frac{1}{2} y^{2} + 8 x + 2 y = 2 :

Right-left Hyperbola with

(h, k) = (- 1, 2), a = 1, b = 22

(- 1 + c, 2), (- 1 - c, 2)

Compute

c :

c = 1^{2} + (22)^{2} : 3

(- 1 + 3, 2), (- 1 - 3, 2)

Refine

(2, 2), (- 4, 2)

\frac{x ^{2}}{9} - \frac{y ^{2}}{40} = 1

16 y^{2} - 32 y - 9 x^{2} - 18 x = 137

\frac{x ^{2}}{9} - \frac{y ^{2}}{1} = 1

25 y^{2} - x^{2} = 100

- 3 x^{2} + 2 y^{2} + 6 x - 7 y = 7

What is the foci 4x^2-1/2 y^2+8x+2y=2 ?
The foci 4x^2-1/2 y^2+8x+2y=2 is (2,2),(-4,2)