What is the foci (x^2)/9-(y^2)/7 =1 ?

The foci (x^2)/9-(y^2)/7 =1 is (4,0),(-4,0)

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foci (x^2)/9-(y^2)/7 =1

foci

\frac{x ^{2}}{9} - \frac{y ^{2}}{7} = 1

(4, 0), (- 4, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{9} - \frac{y ^{2}}{7} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 3, b = 7

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 3^{2} + 7^{2} : 4

(0 + 4, 0), (0 - 4, 0)

Refine

(4, 0), (- 4, 0)

\frac{x ^{2}}{100} - \frac{y ^{2}}{64} = 1

y^{2} - \frac{x ^{2}}{4} = 1

- 9 x^{2} + 4 y^{2} - 36 x - 16 y - 164 = 0

\frac{( x + 5 ) ^{2}}{4} - \frac{y ^{2}}{4} = 1

- \frac{( x - 2 ) ^{2}}{9} + \frac{( y + 1 ) ^{2}}{5} = 1

What is the foci (x^2)/9-(y^2)/7 =1 ?
The foci (x^2)/9-(y^2)/7 =1 is (4,0),(-4,0)