What is x^2+8y+x^2-12x+10=0 ?

The solution to x^2+8y+x^2-12x+10=0 is Parabola with (h,k)=(3,1),p=-1

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x^2+8y+x^2-12x+10=0

x^{2} + 8 y + x^{2} - 12 x + 10 = 0

(h, k) = (3, 1), p = - 1

Solution steps

x^{2} + 8 y + x^{2} - 12 x + 10 = 0

Rewrite

x^{2} + 8 y + x^{2} - 12 x + 10 = 0

in the standard form

4 (- 1) (y - 1) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, 1), p = - 1

x^{2} + y = 64

y - 1 = x^{2}

y^{2} = - x - 2

x - y^{2} = 18

x^{2} = - y + 16

What is x^2+8y+x^2-12x+10=0 ?
The solution to x^2+8y+x^2-12x+10=0 is Parabola with (h,k)=(3,1),p=-1