What is the foci 9x^2-16y^2+36x+32y-124=0 ?

The foci 9x^2-16y^2+36x+32y-124=0 is (3,1),(-7,1)

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foci 9x^2-16y^2+36x+32y-124=0

foci

9 x^{2} - 16 y^{2} + 36 x + 32 y - 124 = 0

(3, 1), (- 7, 1)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

9 x^{2} - 16 y^{2} + 36 x + 32 y - 124 = 0 :

Right-left Hyperbola with

(h, k) = (- 2, 1), a = 4, b = 3

(- 2 + c, 1), (- 2 - c, 1)

Compute

c :

c = 4^{2} + 3^{2} : 5

(- 2 + 5, 1), (- 2 - 5, 1)

Refine

(3, 1), (- 7, 1)

- \frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1

100 x^{2} + 112952 x - 100 y^{2} - 106 y = 48838

4 x^{2} - 25 y^{2} + 16 x + 50 y - 109 = 0

9 x^{2} - 18 x - 24 y - 63 = 4 y^{2}

36 x^{2} - 25 y^{2} = 900

What is the foci 9x^2-16y^2+36x+32y-124=0 ?
The foci 9x^2-16y^2+36x+32y-124=0 is (3,1),(-7,1)