What is the foci (x^2}{1^2}-\frac{y^2)/8 =1 ?

The foci (x^2}{1^2}-\frac{y^2)/8 =1 is (3,0),(-3,0)

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foci (x^2}{1^2}-\frac{y^2)/8 =1

foci

\frac{x ^{2}}{1 ^{2}} - \frac{y ^{2}}{8} = 1

(3, 0), (- 3, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{1 ^{2}} - \frac{y ^{2}}{8} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 1, b = 22

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 1^{2} + (22)^{2} : 3

(0 + 3, 0), (0 - 3, 0)

Refine

(3, 0), (- 3, 0)

3 x^{2} - 15 y^{2} + 2 x - 3 y = 4

\frac{y ^{2}}{4} - \frac{x ^{2}}{9} = 1

\frac{( x - 5 ) ^{2}}{1} - \frac{( y - 4 ) ^{2}}{1} = 1

9 x^{2} - 4 y^{2} - 54 x - 8 y + 113 = 0

\frac{( y - 2 ) ^{2}}{9} - \frac{( x - 1 ) ^{2}}{16} = 1

What is the foci (x^2}{1^2}-\frac{y^2)/8 =1 ?
The foci (x^2}{1^2}-\frac{y^2)/8 =1 is (3,0),(-3,0)