What is the foci 4y^2-9x^2=36 ?

The foci 4y^2-9x^2=36 is (0,sqrt(13)),(0,-sqrt(13))

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foci 4y^2-9x^2=36

foci

4 y^{2} - 9 x^{2} = 36

(0, 13), (0, - 13)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

4 y^{2} - 9 x^{2} = 36 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 3, b = 2

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 3^{2} + 2^{2} : 13

(0, 0 + 13), (0, 0 - 13)

Refine

(0, 13), (0, - 13)

9 x^{2} - y^{2} = 36

\frac{( y - 2 ) ^{2}}{4} - \frac{( x + 3 ) ^{2}}{9} = 1

16 x^{2} - 20 y^{2} - 320 = 0

\frac{x ^{2}}{25} - \frac{y ^{2}}{121} = 1

5 y^{2} - 4 x^{2} - 80 = 0

What is the foci 4y^2-9x^2=36 ?
The foci 4y^2-9x^2=36 is (0,sqrt(13)),(0,-sqrt(13))