What is the foci (y^2)/(36)-(x^2)/(49)=1 ?

The foci (y^2)/(36)-(x^2)/(49)=1 is (0,sqrt(85)),(0,-sqrt(85))

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foci (y^2)/(36)-(x^2)/(49)=1

foci

\frac{y ^{2}}{36} - \frac{x ^{2}}{49} = 1

(0, 85), (0, - 85)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{36} - \frac{x ^{2}}{49} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 6, b = 7

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 6^{2} + 7^{2} : 85

(0, 0 + 85), (0, 0 - 85)

Refine

(0, 85), (0, - 85)

\frac{( x + 2 ) ^{2}}{16} - \frac{( y - 3 ) ^{2}}{25} = 1

\frac{( x - 8 ) ^{2}}{9} - \frac{( y + 3 ) ^{2}}{16} = 1

y^{2} - x^{2} = 4

\frac{( x - 3 ) ^{2}}{3} - \frac{( y - 2 ) ^{2}}{4} = 1

x^{2} - 9 y^{2} = 9

What is the foci (y^2)/(36)-(x^2)/(49)=1 ?
The foci (y^2)/(36)-(x^2)/(49)=1 is (0,sqrt(85)),(0,-sqrt(85))