What is the foci x^2-4y^2=16 ?

The foci x^2-4y^2=16 is (2sqrt(5),0),(-2sqrt(5),0)

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foci x^2-4y^2=16

foci

x^{2} - 4 y^{2} = 16

(25, 0), (- 25, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

x^{2} - 4 y^{2} = 16 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 4, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 4^{2} + 2^{2} : 25

(0 + 25, 0), (0 - 25, 0)

Refine

(25, 0), (- 25, 0)

\frac{( x - 5 ) ^{2}}{12} - \frac{( y + 6 ) ^{2}}{17} = 1

x^{2} - \frac{y ^{2}}{4} = 1

\frac{y ^{2}}{49} - \frac{x ^{2}}{16} = 1

25 x^{2} - 16 y^{2} + 250 x + 32 y + 109 = 0

\frac{( x + 2 ) ^{2}}{25} - \frac{( y - 1 ) ^{2}}{169} = 1

What is the foci x^2-4y^2=16 ?
The foci x^2-4y^2=16 is (2sqrt(5),0),(-2sqrt(5),0)