What is the foci (y^2)/(25)-x^2=1 ?

The foci (y^2)/(25)-x^2=1 is (0,sqrt(26)),(0,-sqrt(26))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (y^2)/(25)-x^2=1

foci

\frac{y ^{2}}{25} - x^{2} = 1

(0, 26), (0, - 26)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{25} - x^{2} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 1

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 5^{2} + 1^{2} : 26

(0, 0 + 26), (0, 0 - 26)

Refine

(0, 26), (0, - 26)

\frac{x ^{2}}{16} - \frac{y ^{2}}{48} = 1

\frac{( y - 1 ) ^{2}}{9} - \frac{( x - 3 ) ^{2}}{16} = 1

\frac{( y + 3 ) ^{2}}{9} - \frac{( x - 1 ) ^{2}}{18} = 1

\frac{( y - 3 ) ^{2}}{9} - \frac{( x + 1 ) ^{2}}{27} = 1

y^{2} - 4 y - 4 x^{2} + 13 = 0

What is the foci (y^2)/(25)-x^2=1 ?
The foci (y^2)/(25)-x^2=1 is (0,sqrt(26)),(0,-sqrt(26))