What is the foci y^2-4x^2=16 ?

The foci y^2-4x^2=16 is (0,2sqrt(5)),(0,-2sqrt(5))

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foci y^2-4x^2=16

foci

y^{2} - 4 x^{2} = 16

(0, 25), (0, - 25)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

y^{2} - 4 x^{2} = 16 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 4, b = 2

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 4^{2} + 2^{2} : 25

(0, 0 + 25), (0, 0 - 25)

Refine

(0, 25), (0, - 25)

\frac{y ^{2}}{4 ^{2}} - \frac{x ^{2}}{3 ^{2}} = 1

x^{2} - \frac{y ^{2}}{25} = 1

x^{2} - 9 y^{2} = 144

\frac{( x - 1 ) ^{2}}{25} - \frac{( y + 3 ) ^{2}}{9} = 1

\frac{( x - 3 ) ^{2}}{3} - \frac{( y - 2 ) ^{2}}{22} = 1

What is the foci y^2-4x^2=16 ?
The foci y^2-4x^2=16 is (0,2sqrt(5)),(0,-2sqrt(5))